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Popular >

d/(dθ)(cos(2θ)+isin(2θ))

Solution

\frac{d}{d θ} (cos (2 θ) + i sin (2 θ))

Solution

- sin (2 θ) \cdot 2 + i cos (2 θ) \cdot 2

Solution steps

\frac{d}{d θ} (cos (2 θ) + i sin (2 θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (cos (2 θ)) + \frac{d}{d θ} (i sin (2 θ))

\frac{d}{d θ} (cos (2 θ)) = - sin (2 θ) \cdot 2

\frac{d}{d θ} (i sin (2 θ)) = i cos (2 θ) \cdot 2

= - sin (2 θ) \cdot 2 + i cos (2 θ) \cdot 2

Popular Examples

derivative of (3x-x^2(3-x-x^2))

\frac{d}{d x} ((3 x - x^{2}) (3 - x - x^{2}))

integral of (x^2+84x+84)/(x^3-4x)

\int \frac{x ^{2} + 84 x + 84}{x ^{3} - 4 x} d x

(\partial)/(\partial x)(3x^4+5x^4+9xy)

\frac{\partial}{\partial x} (3 x^{4} + 5 x^{4} + 9 x y)

(\partial)/(\partial s)(7/s)

\frac{\partial}{\partial s} (\frac{7}{s})

derivative of h(x)=x^3+4x^4 derivative of

h (x) = x^{3} + 4 x^{4}

Frequently Asked Questions (FAQ)

What is the d/(dθ)(cos(2θ)+isin(2θ)) ?
The d/(dθ)(cos(2θ)+isin(2θ)) is -sin(2θ)*2+icos(2θ)*2
What is the first d/(dθ)(cos(2θ)+isin(2θ)) ?
The first d/(dθ)(cos(2θ)+isin(2θ)) is -sin(2θ)*2+icos(2θ)*2