What is the derivative of h(x)=x^3+4x^4 ?

The derivative of h(x)=x^3+4x^4 is 3x^2+16x^3

What is the first derivative of h(x)=x^3+4x^4 ?

The first derivative of h(x)=x^3+4x^4 is 3x^2+16x^3

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derivative of

h (x) = x^{3} + 4 x^{4}

3 x^{2} + 16 x^{3}

Solution steps

\frac{d}{d x} (x^{3} + 4 x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (4 x^{4})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x^{4}) = 16 x^{3}

= 3 x^{2} + 16 x^{3}

f (t) = sin (2 t)

0.04 t^{3} - 0.12 t^{2}

x \to 3 - lim (\frac{x + 2}{x ^{2} - 9})

x + 8

What is the derivative of h(x)=x^3+4x^4 ?
The derivative of h(x)=x^3+4x^4 is 3x^2+16x^3
What is the first derivative of h(x)=x^3+4x^4 ?
The first derivative of h(x)=x^3+4x^4 is 3x^2+16x^3