What is the derivative of sqrt(x+8) ?

The derivative of sqrt(x+8) is 1/(2sqrt(x+8))

What is the first derivative of sqrt(x+8) ?

The first derivative of sqrt(x+8) is 1/(2sqrt(x+8))

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derivative of

x + 8

\frac{1}{2 x + 8}

Solution steps

\frac{d}{d x} (x + 8)

Apply the chain rule:

\frac{1}{2 x + 8} \frac{d}{d x} (x + 8)

= \frac{1}{2 x + 8} \frac{d}{d x} (x + 8)

\frac{d}{d x} (x + 8) = 1

= \frac{1}{2 x + 8} \cdot 1

Simplify

= \frac{1}{2 x + 8}

\frac{\partial}{\partial x} (e^{\frac{x}{y}})

\frac{\partial}{\partial r} (r sin (t) sin (x))

\int_{0}^{1} \frac{17}{4 y - 1} d y

\frac{6}{s} + 8 a \cdot \frac{s}{s ^{2} + 16}

What is the derivative of sqrt(x+8) ?
The derivative of sqrt(x+8) is 1/(2sqrt(x+8))
What is the first derivative of sqrt(x+8) ?
The first derivative of sqrt(x+8) is 1/(2sqrt(x+8))