What is area sin(x),cos(x),[0,2pi] ?

The answer to area sin(x),cos(x),[0,2pi] is 4sqrt(2)

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area sin(x),cos(x),[0,2pi]

area

sin (x), cos (x), [0, 2 π]

42

Decimal Notation

5.65685 \dots

Solution steps

Apply the area formula:

\int_{0}^{2 π} ∣ sin (x) - cos (x) ∣ d x

Solve

\int_{0}^{2 π} ∣ sin (x) - cos (x) ∣ d x : 42

The area is:

= 42

(x^{2} + y) + (x + e^{y}) \frac{d y}{d x} = 0

\int \frac{3 y ^{2} + 1}{y ^{3} + y} d y

\int sin^{3} (x) d x

x \to - 2 lim (x (x - 1))

What is area sin(x),cos(x),[0,2pi] ?
The answer to area sin(x),cos(x),[0,2pi] is 4sqrt(2)