What is the derivative of 8-x^3 ?

The derivative of 8-x^3 is -3x^2

What is the first derivative of 8-x^3 ?

The first derivative of 8-x^3 is -3x^2

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\frac{d}{d x} (8 - x^{3})

- 3 x^{2}

Solution steps

\frac{d}{d x} (8 - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (8) = 0

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 0 - 3 x^{2}

Simplify

= - 3 x^{2}

f (x) = \frac{3}{x}, at x = - 2

k = 1 \sum \infty \frac{x ^{k}}{k 3 ^{k}}

\int (x^{2} - 5)^{2} 2 x d x

7 x y^{^{'}} = 2 x e^{x} - 7 y + 6 x^{2}

\frac{\partial}{\partial x} (2 x)