What is the first derivative of 4x+9 ?

The first derivative of 4x+9 is 4

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derivative of 4x+9

derivative of

4 x + 9

4

Solution steps

\frac{d}{d x} (4 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (9)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (9) = 0

= 4 + 0

Simplify

= 4

\int (4 x - 3)^{5} d x

\int cos (n wt) d t

y^{^{''}} + 9 y = 3 sin (3 t)

y = (1 - e^{x})^{4}

\frac{\partial}{\partial x} (\frac{1}{2} m v^{2})