What is the solution for y^{''}+9y=3sin(3t) ?

The solution for y^{''}+9y=3sin(3t) is y=c_{1}cos(3t)+c_{2}sin(3t)-(tcos(3t))/2

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y^{''}+9y=3sin(3t)

y^{^{''}} + 9 y = 3 sin (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{t cos ( 3 t )}{2}

Solution steps

y^{''} (t) + 9 y = 3 sin (3 t)

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{t cos ( 3 t )}{2}

y = c_{1} cos (3 t) + c_{2} sin (3 t) - \frac{t cos ( 3 t )}{2}

y = (1 - e^{x})^{4}

\frac{\partial}{\partial x} (\frac{1}{2} m v^{2})

y (θ) = 2 - θ^{5} sin (θ)

500 (3 + \frac{5 t}{30 + t ^{2}})

\int π (y + 2)^{2} d y

What is the solution for y^{''}+9y=3sin(3t) ?
The solution for y^{''}+9y=3sin(3t) is y=c_{1}cos(3t)+c_{2}sin(3t)-(tcos(3t))/2