What is the derivative of x^3+2x^4 ?

The derivative of x^3+2x^4 is 3x^2+8x^3

What is the first derivative of x^3+2x^4 ?

The first derivative of x^3+2x^4 is 3x^2+8x^3

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\frac{d}{d x} (x^{3} + 2 x^{4})

3 x^{2} + 8 x^{3}

Solution steps

\frac{d}{d x} (x^{3} + 2 x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{4})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

= 3 x^{2} + 8 x^{3}

\int \frac{x ^{5}}{1 - x ^{6}} d x

\frac{d}{d x} (24 x^{\frac{1}{2}})

\frac{\partial}{\partial y} (x e^{y - z})

\frac{d}{d x} (- e^{- x} - e^{- x} x)

\frac{d y}{d x} = 0.0017 y (900 - y)

What is the derivative of x^3+2x^4 ?
The derivative of x^3+2x^4 is 3x^2+8x^3
What is the first derivative of x^3+2x^4 ?
The first derivative of x^3+2x^4 is 3x^2+8x^3