What is the limit as x approaches 0 of In(1+sin(x)) ?

The limit as x approaches 0 of In(1+sin(x)) is nI

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of In(1+sin(x))

x \to 0 lim (I n (1 + sin (x)))

n I

Solution steps

x \to 0 lim (I n (1 + sin (x)))

Plug in the value

x = 0

= I n (1 + sin (0))

Simplify

I n (1 + sin (0)) : n I

= n I

\frac{d}{d x} (\frac{x ^{3} + 2}{x})

y = ln (7 x^{2} + 3 y^{2})

2 y^{^{''}} + 3 y^{^{'}} + y = t^{2} + 3 sin (t)

\int \frac{( 3 \cdot ln ( x ) - 5 ) ^{4}}{x} d x

What is the limit as x approaches 0 of In(1+sin(x)) ?
The limit as x approaches 0 of In(1+sin(x)) is nI