What is the derivative of 1-3x^2 ?

The derivative of 1-3x^2 is -6x

What is the first derivative of 1-3x^2 ?

The first derivative of 1-3x^2 is -6x

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derivative of

1 - 3 x^{2}

- 6 x

Solution steps

\frac{d}{d x} (1 - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3 x^{2}) = 6 x

= 0 - 6 x

Simplify

= - 6 x

12 x^{3} - 3 y x^{4} + 1 \frac{d y}{d x} = 0

\int_{0}^{4} 2^{s} d s

y^{^{'}} + 3 y = e^{- 4 t}

\int_{0}^{2} 4 x - x^{3} d x

e^{t} (cos (t))