What is the integral from 0 to 4 of 2^s ?

The integral from 0 to 4 of 2^s is (15)/(ln(2))

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integral from 0 to 4 of 2^s

\int_{0}^{4} 2^{s} d s

\frac{15}{ln ( 2 )}

Decimal Notation

21.64042 \dots

Solution steps

\int_{0}^{4} 2^{s} d s

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{s}}{ln ( 2 )}]_{0}^{4}

Compute the boundaries:

\frac{15}{ln ( 2 )}

= \frac{15}{ln ( 2 )}

y^{^{'}} + 3 y = e^{- 4 t}

\int_{0}^{2} 4 x - x^{3} d x

e^{t} (cos (t))

x = - 2, x = 2, y = 2 x^{2} + 5, y = 0

sin (- 1 (6 x + 1))

What is the integral from 0 to 4 of 2^s ?
The integral from 0 to 4 of 2^s is (15)/(ln(2))