What is area x=-2,x=2,y=2x^2+5,y=0 ?

The answer to area x=-2,x=2,y=2x^2+5,y=0 is 92/3

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area x=-2,x=2,y=2x^2+5,y=0

area

x = - 2, x = 2, y = 2 x^{2} + 5, y = 0

\frac{92}{3}

Decimal Notation

30.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} 2 x^{2} + 5 d x

Solve

\int_{- 2}^{2} 2 x^{2} + 5 d x : \frac{92}{3}

The area is:

= \frac{92}{3}

sin (- 1 (6 x + 1))

\frac{2}{s ( s + 2 )}

\int \frac{cos ( x )}{( sin ( x ) ) ^{3}} d x

x \to - 7 + lim (\frac{( - 6 x )}{x + 7})

\frac{d ^{2}}{d x ^{2}} (ln (x^{2} + 1))

What is area x=-2,x=2,y=2x^2+5,y=0 ?
The answer to area x=-2,x=2,y=2x^2+5,y=0 is 92/3