What is the derivative of arcsec(e^x) ?

The derivative of arcsec(e^x) is 1/(sqrt(e^{2x)-1)}

What is the first derivative of arcsec(e^x) ?

The first derivative of arcsec(e^x) is 1/(sqrt(e^{2x)-1)}

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\frac{d}{d x} (arcsec (e^{x}))

\frac{1}{e ^{2 x} - 1}

Solution steps

\frac{d}{d x} (arcsec (e^{x}))

Apply the chain rule:

\frac{1}{( e ^{x} ) ^{2} ( e ^{x} ) ^{2} - 1} \frac{d}{d x} (e^{x})

= \frac{1}{( e ^{x} ) ^{2} ( e ^{x} ) ^{2} - 1} \frac{d}{d x} (e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

= \frac{1}{( e ^{x} ) ^{2} ( e ^{x} ) ^{2} - 1} e^{x}

Simplify

\frac{1}{( e ^{x} ) ^{2} ( e ^{x} ) ^{2} - 1} e^{x} : \frac{1}{e ^{2 x} - 1}

= \frac{1}{e ^{2 x} - 1}

(2) (1)

\int_{2}^{1} x^{2} d x

x \to 1 + lim (\frac{1}{x})

\frac{d}{d x} (e^{5 - x})

f (x) = 22 x^{\frac{3}{2}} - 8 x^{\frac{1}{2}}

What is the derivative of arcsec(e^x) ?
The derivative of arcsec(e^x) is 1/(sqrt(e^{2x)-1)}
What is the first derivative of arcsec(e^x) ?
The first derivative of arcsec(e^x) is 1/(sqrt(e^{2x)-1)}