What is the integral of sin(1/6)xsin(1/12)x ?

The integral of sin(1/6)xsin(1/12)x is 1/3 sin(1/6)sin(1/12)x^3+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sin(1/6)xsin(1/12)x

\int sin (\frac{1}{6}) x sin (\frac{1}{12}) x d x

\frac{1}{3} sin (\frac{1}{6}) sin (\frac{1}{12}) x^{3} + C

Solution steps

\int sin (\frac{1}{6}) x sin (\frac{1}{12}) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (\frac{1}{6}) sin (\frac{1}{12}) \cdot \int xx d x

Simplify

xx : x^{2}

= sin (\frac{1}{6}) sin (\frac{1}{12}) \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= sin (\frac{1}{6}) sin (\frac{1}{12}) \frac{x ^{3}}{3}

Simplify

sin (\frac{1}{6}) sin (\frac{1}{12}) \frac{x ^{3}}{3} : \frac{1}{3} sin (\frac{1}{6}) sin (\frac{1}{12}) x^{3}

= \frac{1}{3} sin (\frac{1}{6}) sin (\frac{1}{12}) x^{3}

Add a constant to the solution

= \frac{1}{3} sin (\frac{1}{6}) sin (\frac{1}{12}) x^{3} + C

x \to 0 lim (\frac{3 e ^{x}}{x + 1})

y^{^{'}} = x^{2} + 4

\frac{d}{d x} (\frac{x}{1 + ( 1.5574 + 6.09 x ^{2} ) ^{2}})

\frac{\partial}{\partial x} (e^{x} + y cos (x y))

\int (- \frac{1}{x}) d x

What is the integral of sin(1/6)xsin(1/12)x ?
The integral of sin(1/6)xsin(1/12)x is 1/3 sin(1/6)sin(1/12)x^3+C