What is the solution for (dy)/(dx)=-2xy^2,y(1)= 1/4 ?

The solution for (dy)/(dx)=-2xy^2,y(1)= 1/4 is y= 1/(x^2+3)

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(dy)/(dx)=-2xy^2,y(1)= 1/4

\frac{d y}{d x} = - 2 x y^{2}, y (1) = \frac{1}{4}

y = \frac{1}{x ^{2} + 3}

Solution steps

\frac{d y}{d x} = - 2 x y^{2}

Solve separable ODE:

y = \frac{1}{x ^{2} + 3}

y = \frac{1}{x ^{2} + 3}

\frac{d}{d x} (\frac{5 x}{x ^{2} - 1})

x \to \infty lim (2 x^{2})

\int 2 x e^{8 x} d x

\int_{0}^{2} (x^{2} - 7 x) d x

\frac{d}{d x} (7 x + 2)

What is the solution for (dy)/(dx)=-2xy^2,y(1)= 1/4 ?
The solution for (dy)/(dx)=-2xy^2,y(1)= 1/4 is y= 1/(x^2+3)