What is the derivative of x^3-3x^2 ?

The derivative of x^3-3x^2 is 3x^2-6x

What is the first derivative of x^3-3x^2 ?

The first derivative of x^3-3x^2 is 3x^2-6x

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\frac{d}{d x} (x^{3} - 3 x^{2})

3 x^{2} - 6 x

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

= 3 x^{2} - 6 x

\frac{5 t + 300}{t ^{2} + 25}

\frac{d}{d x} (\frac{x - 2}{2 x + 1})

f (x) = 2 x - 5 x, (4, - 2)

h \to 0 lim (3 x^{2} + 2 x h + h^{2})

\int 20 x ln (x) d x

What is the derivative of x^3-3x^2 ?
The derivative of x^3-3x^2 is 3x^2-6x
What is the first derivative of x^3-3x^2 ?
The first derivative of x^3-3x^2 is 3x^2-6x