What is the derivative of y=-ln(x) ?

The derivative of y=-ln(x) is -1/x

What is the first derivative of y=-ln(x) ?

The first derivative of y=-ln(x) is -1/x

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derivative of

y = - ln (x)

- \frac{1}{x}

Solution steps

\frac{d}{d x} (- ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (ln (x))

Apply the common derivative:

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= - \frac{1}{x}

x \to 0 lim (\frac{sin ( 8 x )}{sin ( 7 x )})

\frac{d}{d x} (x^{2} + y)

\frac{\partial}{\partial x} (arccos (\frac{y}{x}))

y^{^{'}} x^{2} - 18 = 4 x

\frac{d}{d x} (\frac{( 6 x ^{2} + 2 x + 8 )}{x})

What is the derivative of y=-ln(x) ?
The derivative of y=-ln(x) is -1/x
What is the first derivative of y=-ln(x) ?
The first derivative of y=-ln(x) is -1/x