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Popular >

y^'sqrt(x^2-18)=4x

Solution

y^{^{'}} x^{2} - 18 = 4 x

Solution

y = 4 x^{2} - 18 + c_{1}

Solution steps

y^{'} (x) x^{2} - 18 = 4 x

Isolate

y^{'} (x) : y^{'} (x) = \frac{4 x}{x ^{2} - 18}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{4 x}{x ^{2} - 18} d x

\int \frac{4 x}{x ^{2} - 18} d x = 4 x^{2} - 18 + c_{1}

y = 4 x^{2} - 18 + c_{1}

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Frequently Asked Questions (FAQ)

What is the solution for y^'sqrt(x^2-18)=4x ?
The solution for y^'sqrt(x^2-18)=4x is y=4sqrt(x^2-18)+c_{1}