What is the integral from 1 to 2 of (-9x^2+4x) ?

The integral from 1 to 2 of (-9x^2+4x) is -15

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integral from 1 to 2 of (-9x^2+4x)

\int_{1}^{2} (- 9 x^{2} + 4 x) d x

- 15

Solution steps

\int_{1}^{2} - 9 x^{2} + 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{2} 9 x^{2} d x + \int_{1}^{2} 4 x d x

\int_{1}^{2} 9 x^{2} d x = 21

\int_{1}^{2} 4 x d x = 6

= - 21 + 6

Simplify

= - 15

x \to 0 lim (\frac{4}{x + 4 h})

f (x) = 4 x^{2} + 3 x, (- 3, 27)

x \to \infty lim (2 x - x^{2})

\frac{\partial}{\partial x} (e^{2 x yz - 3})

y^{^{'}} = 9 y^{2}

What is the integral from 1 to 2 of (-9x^2+4x) ?
The integral from 1 to 2 of (-9x^2+4x) is -15