What is the limit as x approaches 0 of 4/(x+4h) ?

The limit as x approaches 0 of 4/(x+4h) is 1/h

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limit as x approaches 0 of 4/(x+4h)

x \to 0 lim (\frac{4}{x + 4 h})

\frac{1}{h}

Solution steps

x \to 0 lim (\frac{4}{x + 4 h})

Plug in the value

x = 0

= \frac{4}{0 + 4 h}

Simplify

= \frac{1}{h}

f (x) = 4 x^{2} + 3 x, (- 3, 27)

x \to \infty lim (2 x - x^{2})

\frac{\partial}{\partial x} (e^{2 x yz - 3})

y^{^{'}} = 9 y^{2}

\int \frac{2}{( x ^{2} + 2 ) ^{2}} d x

What is the limit as x approaches 0 of 4/(x+4h) ?
The limit as x approaches 0 of 4/(x+4h) is 1/h