What is (\partial)/(\partial z)(3ycos(pix)+2xz) ?

The answer to (\partial)/(\partial z)(3ycos(pix)+2xz) is 2x

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(\partial)/(\partial z)(3ycos(pix)+2xz)

\frac{\partial}{\partial z} (3 y cos (π x) + 2 x z)

2 x

Solution steps

\frac{\partial}{\partial z} (3 y cos (π x) + 2 x z)

Treat

y, x

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (3 y cos (π x)) + \frac{\partial}{\partial z} (2 x z)

\frac{\partial}{\partial z} (3 y cos (π x)) = 0

\frac{\partial}{\partial z} (2 x z) = 2 x

= 0 + 2 x

Simplify

= 2 x

\frac{d}{d x} (\frac{3}{3 x - 5})

\int \frac{1}{( x + 3 ) ^{2} ( x - 4 )} d x

\frac{d}{d x} (x + \frac{4}{x ^{2}})

\frac{d}{d x} (\frac{sin ( x ^{2} )}{x})

\frac{\partial}{\partial x} ((x + 2 y)^{2})

What is (\partial)/(\partial z)(3ycos(pix)+2xz) ?
The answer to (\partial)/(\partial z)(3ycos(pix)+2xz) is 2x