What is the tangent of f(x)=x^4,(-1,1) ?

The tangent of f(x)=x^4,(-1,1) is y=-4x-3

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tangent of f(x)=x^4,(-1,1)

tangent of

f (x) = x^{4}, (- 1, 1)

y = - 4 x - 3

Solution steps

Find the slope of

f (x) = x^{4} : \frac{df ( x )}{d x} = 4 x^{3}

Compute the slope of

f (x) = x^{4}

(- 1, 1) : m = - 4

Find the line with slope m=

- 4

and passing through

(- 1, 1) : y = - 4 x - 3

y = - 4 x - 3

y = 4 x - 2 x^{2}

\frac{d}{d x} ((a x + b)^{n})

f (x) = \frac{x ^{2}}{2} + 2 x + 4

f^{^{'}} (x) = \frac{9}{2 9 x - 5}

\int \frac{1}{x ^{2} 25 - x ^{2}} d x

What is the tangent of f(x)=x^4,(-1,1) ?
The tangent of f(x)=x^4,(-1,1) is y=-4x-3