What is (\partial}{\partial x}(sin(\frac{4x)/y)) ?

The answer to (\partial}{\partial x}(sin(\frac{4x)/y)) is (4cos((4x)/y))/(y)

Popular >

(\partial}{\partial x}(sin(\frac{4x)/y))

\frac{\partial}{\partial x} (sin (\frac{4 x}{y}))

\frac{4 cos ( \frac{4 x}{y} )}{y}

Solution steps

\frac{\partial}{\partial x} (sin (\frac{4 x}{y}))

Treat

y

as a constant

Apply the chain rule:

cos (\frac{4 x}{y}) \frac{\partial}{\partial x} (\frac{4 x}{y})

= cos (\frac{4 x}{y}) \frac{\partial}{\partial x} (\frac{4 x}{y})

\frac{\partial}{\partial x} (\frac{4 x}{y}) = \frac{4}{y}

= cos (\frac{4 x}{y}) \frac{4}{y}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{4 cos ( \frac{4 x}{y} )}{y}

\int x^{2} - 17 d x

\int cos^{8} (3 x) sin^{3} (3 x) d x

(3 x - 3 x^{2}) tan (x)

9 (t + 1) (\frac{d y}{d t}) - 6 y = 18 t

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

What is (\partial}{\partial x}(sin(\frac{4x)/y)) ?
The answer to (\partial}{\partial x}(sin(\frac{4x)/y)) is (4cos((4x)/y))/(y)