What is the integral of (D(5x^2+5y^2)-1)/2 ?

The integral of (D(5x^2+5y^2)-1)/2 is (-1+(5x^2+5y^2)D)/2 A+C

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integral of (D(5x^2+5y^2)-1)/2

\int \frac{D ( 5 x ^{2} + 5 y ^{2} ) - 1}{2} d A

\frac{- 1 + ( 5 x ^{2} + 5 y ^{2} ) D}{2} A + C

Solution steps

\int \frac{D ( 5 x ^{2} + 5 y ^{2} ) - 1}{2} d A

Integral of a constant:

\int a d x = a x

= \frac{- 1 + ( 5 x ^{2} + 5 y ^{2} ) D}{2} A

Add a constant to the solution

= \frac{- 1 + ( 5 x ^{2} + 5 y ^{2} ) D}{2} A + C

x y^{^{'}} + 2 y = 3 sin (x)

\int \frac{e ^{2 x}}{e ^{4 x} + 4} d x

\int_{1}^{\infty} e^{- 5 x} d x

\frac{d}{d x} (3 - 4 sin (2 x + \frac{π}{4}))

\frac{d}{d x} (e^{0.4 x} \cdot sin (0.2 x))

What is the integral of (D(5x^2+5y^2)-1)/2 ?
The integral of (D(5x^2+5y^2)-1)/2 is (-1+(5x^2+5y^2)D)/2 A+C