What is the derivative of 3-4sin(2x+pi/4) ?

The derivative of 3-4sin(2x+pi/4) is -2(2sqrt(2)cos(2x)-2sqrt(2)sin(2x))

What is the first derivative of 3-4sin(2x+pi/4) ?

The first derivative of 3-4sin(2x+pi/4) is -2(2sqrt(2)cos(2x)-2sqrt(2)sin(2x))

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\frac{d}{d x} (3 - 4 sin (2 x + \frac{π}{4}))

- 2 (22 cos (2 x) - 22 sin (2 x))

Solution steps

\frac{d}{d x} (3 - 4 sin (2 x + \frac{π}{4}))

Simplify

3 - 4 sin (2 x + \frac{π}{4}) : 3 - 2 (2 sin (2 x) + 2 cos (2 x))

= \frac{d}{d x} (3 - 2 (2 sin (2 x) + 2 cos (2 x)))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d}{d x} (2 (2 sin (2 x) + 2 cos (2 x)))

\frac{d}{d x} (3) = 0

\frac{d}{d x} (2 (2 sin (2 x) + 2 cos (2 x))) = 2 (2 cos (2 x) \cdot 2 - 22 sin (2 x))

= 0 - 2 (2 cos (2 x) \cdot 2 - 22 sin (2 x))

Simplify

= - 2 (22 cos (2 x) - 22 sin (2 x))

\frac{d}{d x} (e^{0.4 x} \cdot sin (0.2 x))

\frac{\partial}{\partial x} (x^{2} + 2 y^{2} + 7 z^{2})

\int \frac{1}{16 + 9 x ^{2}} d x

\frac{17}{x}

\int (x^{3} + 2 x) d x

What is the derivative of 3-4sin(2x+pi/4) ?
The derivative of 3-4sin(2x+pi/4) is -2(2sqrt(2)cos(2x)-2sqrt(2)sin(2x))
What is the first derivative of 3-4sin(2x+pi/4) ?
The first derivative of 3-4sin(2x+pi/4) is -2(2sqrt(2)cos(2x)-2sqrt(2)sin(2x))