What is the derivative of (17)/x ?

The derivative of (17)/x is -(17)/(x^2)

What is the first derivative of (17)/x ?

The first derivative of (17)/x is -(17)/(x^2)

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derivative of

\frac{17}{x}

- \frac{17}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{17}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 17 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 17 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 17 (- 1 \cdot x^{- 1 - 1})

Simplify

17 (- 1 \cdot x^{- 1 - 1}) : - \frac{17}{x ^{2}}

= - \frac{17}{x ^{2}}

\int (x^{3} + 2 x) d x

y^{^{''}} + 3 (y^{^{'}})^{2} = - 17

\int - 3 e^{- 3 x} d x

\frac{d}{d x} (7 sin (x) + 7 x cos (x))

\int - 3 y^{2} d y

What is the derivative of (17)/x ?
The derivative of (17)/x is -(17)/(x^2)
What is the first derivative of (17)/x ?
The first derivative of (17)/x is -(17)/(x^2)