What is the tangent of cos^3(x),\at x=0 ?

The tangent of cos^3(x),\at x=0 is y=1

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tangent of cos^3(x),\at x=0

tangent of

cos^{3} (x), at x = 0

y = 1

Solution steps

Find the tangent point:

(0, 1)

Find the slope of

y = cos^{3} (x) : \frac{d y}{d x} = - 3 cos^{2} (x) sin (x)

Compute the slope of

y = cos^{3} (x)

x = 0 : m = 0

Find the line with slope m=

0

and passing through

(0, 1) : y = 1

y = 1

\frac{2 x ^{3}}{3} - 12 x

\frac{d}{d x} (\frac{x ^{2}}{x + 5})

f (x) = 5 x^{4}

x \to 0 lim (\frac{2 + x}{2 - x})

\frac{d}{d x} (x (2 x - 1) (3 x + 2))

What is the tangent of cos^3(x),\at x=0 ?
The tangent of cos^3(x),\at x=0 is y=1