What is the integral of y^2(9-y^3)^{2/3} ?

The integral of y^2(9-y^3)^{2/3} is -1/5 (9-y^3)^{5/3}+C

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integral of y^2(9-y^3)^{2/3}

\int y^{2} (9 - y^{3})^{\frac{2}{3}} d y

- \frac{1}{5} (9 - y^{3})^{\frac{5}{3}} + C

Solution steps

\int y^{2} (9 - y^{3})^{\frac{2}{3}} d y

Apply u-substitution

: \int - \frac{u ^{\frac{2}{3}}}{3} d u

= \int - \frac{u ^{\frac{2}{3}}}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{3} \cdot \int u^{\frac{2}{3}} d u

Apply the Power Rule

: \frac{3}{5} u^{\frac{5}{3}}

= - \frac{1}{3} \cdot \frac{3}{5} u^{\frac{5}{3}}

Substitute back

u = 9 - y^{3}

= - \frac{1}{3} \cdot \frac{3}{5} (9 - y^{3})^{\frac{5}{3}}

Simplify

- \frac{1}{3} \cdot \frac{3}{5} (9 - y^{3})^{\frac{5}{3}} : - \frac{1}{5} (9 - y^{3})^{\frac{5}{3}}

= - \frac{1}{5} (9 - y^{3})^{\frac{5}{3}}

Add a constant to the solution

= - \frac{1}{5} (9 - y^{3})^{\frac{5}{3}} + C

\int 12 (2 x + 7) (x + 1)^{2} d x

f (x) = 2 e^{2 x}

x \to 1 - lim ((x - 1)^{2})

\int x^{2} (1 + 2 x^{3})^{5} d x

What is the integral of y^2(9-y^3)^{2/3} ?
The integral of y^2(9-y^3)^{2/3} is -1/5 (9-y^3)^{5/3}+C