What is the derivative of (sin(2x)/(1+cos(2x))) ?

The derivative of (sin(2x)/(1+cos(2x))) is sec^2(x)

What is the first derivative of (sin(2x)/(1+cos(2x))) ?

The first derivative of (sin(2x)/(1+cos(2x))) is sec^2(x)

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\frac{d}{d x} (\frac{sin ( 2 x )}{1 + cos ( 2 x )})

sec^{2} (x)

Solution steps

\frac{d}{d x} (\frac{sin ( 2 x )}{1 + cos ( 2 x )})

Simplify

\frac{sin ( 2 x )}{1 + cos ( 2 x )} : tan (x)

= \frac{d}{d x} (tan (x))

Apply the common derivative:

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= sec^{2} (x)

3 x^{2} - 14 x + 5

\frac{9}{x ^{2} + 2}

\int_{0}^{4} \frac{x}{x ^{2} + 9} d x

\int_{2}^{\infty} \frac{2}{x ^{2} - 1} d x

x \to + 0 lim (ln (x^{2}))

What is the derivative of (sin(2x)/(1+cos(2x))) ?
The derivative of (sin(2x)/(1+cos(2x))) is sec^2(x)
What is the first derivative of (sin(2x)/(1+cos(2x))) ?
The first derivative of (sin(2x)/(1+cos(2x))) is sec^2(x)