What is the derivative of y=(x^2-4x)^5 ?

The derivative of y=(x^2-4x)^5 is 5(x^2-4x)^4(2x-4)

What is the first derivative of y=(x^2-4x)^5 ?

The first derivative of y=(x^2-4x)^5 is 5(x^2-4x)^4(2x-4)

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derivative of

y = (x^{2} - 4 x)^{5}

5 (x^{2} - 4 x)^{4} (2 x - 4)

Solution steps

\frac{d}{d x} ((x^{2} - 4 x)^{5})

Apply the chain rule:

5 (x^{2} - 4 x)^{4} \frac{d}{d x} (x^{2} - 4 x)

= 5 (x^{2} - 4 x)^{4} \frac{d}{d x} (x^{2} - 4 x)

\frac{d}{d x} (x^{2} - 4 x) = 2 x - 4

= 5 (x^{2} - 4 x)^{4} (2 x - 4)

\int_{1}^{\infty} e^{- x} d x

(x^{x^{x^{x}}})^{^{'}}

(7 x + 6 y) d x + (6 x - 8 y 3) d y = 0

x \to 0 lim (\frac{sin ( 7 x )}{x})

\frac{d}{d x} (1 - tan (x))

What is the derivative of y=(x^2-4x)^5 ?
The derivative of y=(x^2-4x)^5 is 5(x^2-4x)^4(2x-4)
What is the first derivative of y=(x^2-4x)^5 ?
The first derivative of y=(x^2-4x)^5 is 5(x^2-4x)^4(2x-4)