What is the limit as x approaches 0 of (sin(7x))/x ?

The limit as x approaches 0 of (sin(7x))/x is 7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (sin(7x))/x

x \to 0 lim (\frac{sin ( 7 x )}{x})

7

Solution steps

x \to 0 lim (\frac{sin ( 7 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{cos ( 7 x ) \cdot 7}{1})

= x \to 0 lim (\frac{cos ( 7 x ) \cdot 7}{1})

Plug in the value

x = 0

= \frac{cos ( 7 \cdot 0 ) \cdot 7}{1}

Simplify

\frac{cos ( 7 \cdot 0 ) \cdot 7}{1} : 7

= 7

\frac{d}{d x} (1 - tan (x))

\frac{d ^{2}}{d x ^{2}} (cos^{2} (4 π x))

y^{^{'''}} - y^{^{''}} - y^{^{'}} = 0

\int 7 x e^{2 x} d x

x \to π lim ((x + π) csc (x))

What is the limit as x approaches 0 of (sin(7x))/x ?
The limit as x approaches 0 of (sin(7x))/x is 7