What is the derivative of (x^2+1^3) ?

The derivative of (x^2+1^3) is 6x(x^2+1)^2

What is the first derivative of (x^2+1^3) ?

The first derivative of (x^2+1^3) is 6x(x^2+1)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((x^{2} + 1)^{3})

6 x (x^{2} + 1)^{2}

Solution steps

\frac{d}{d x} ((x^{2} + 1)^{3})

Apply the chain rule:

3 (x^{2} + 1)^{2} \frac{d}{d x} (x^{2} + 1)

= 3 (x^{2} + 1)^{2} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= 3 (x^{2} + 1)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} + 1)^{2}

\frac{d}{d a} (1 + sin (a) + cos (a))

\frac{d}{d x} (\frac{100 ( x + 25 )}{x})

\int \frac{6 x - 12}{x ^{2}} d x

\frac{50000}{s ^{2}}

\int_{0}^{1} \frac{x ^{2}}{x + 1} d x

What is the derivative of (x^2+1^3) ?
The derivative of (x^2+1^3) is 6x(x^2+1)^2
What is the first derivative of (x^2+1^3) ?
The first derivative of (x^2+1^3) is 6x(x^2+1)^2