What is area y= 4/(x^2+4),[-10,10] ?

The answer to area y= 4/(x^2+4),[-10,10] is 4arctan(5)

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area y= 4/(x^2+4),[-10,10]

area

y = \frac{4}{x ^{2} + 4}, [- 10, 10]

4 arctan (5)

Decimal Notation

5.49360 \dots

Solution steps

Apply the area formula:

\int_{- 10}^{10} \frac{4}{∣ x ^{2} + 4 ∣} d x

Solve

\int_{- 10}^{10} \frac{4}{∣ x ^{2} + 4 ∣} d x : 4 arctan (5)

The area is:

= 4 arctan (5)

\frac{d}{d x} ((x - y)^{2})

4 x - 17

\int \frac{cos ^{2} ( 4 x )}{4} d x

\frac{1}{s} \cdot (\frac{10}{s ^{2} + s + 10})

- 4 e^{3 t}

What is area y= 4/(x^2+4),[-10,10] ?
The answer to area y= 4/(x^2+4),[-10,10] is 4arctan(5)