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Popular >

tangent of x^2=y^2,(1,-1)

Solution

tangent of

x^{2} = y^{2}, (1, - 1)

Solution

y = - x

Solution steps

Find the slope of

x^{2} = y^{2} : \frac{d y}{d x} = \frac{x}{y}

Compute the slope of

x^{2} = y^{2}

at

(1, - 1) : m = - 1

Find the line with slope m=

- 1

and passing through

(1, - 1) : y = - x

y = - x

Popular Examples

tangent of f(x)=x^2-7x+7,\at x=0 tangent of

f (x) = x^{2} - 7 x + 7, at x = 0

(\partial)/(\partial x)(-y*cos(x))

\frac{\partial}{\partial x} (- y \cdot cos (x))

xy^'=(1-4x^2)tan(y)

x y^{^{'}} = (1 - 4 x^{2}) tan (y)

integral of (2e^x)/(e^{2x)+10e^x+25}

\int \frac{2 e ^{x}}{e ^{2 x} + 10 e ^{x} + 25} d x

integral of (x^3)/((x-1)^4)

\int \frac{x ^{3}}{( x - 1 ) ^{4}} d x

Frequently Asked Questions (FAQ)

What is the tangent of x^2=y^2,(1,-1) ?
The tangent of x^2=y^2,(1,-1) is y=-x