What is (d^2)/(dx^2)((x^3+2x)^6) ?

The answer to (d^2)/(dx^2)((x^3+2x)^6) is 6(5(x^3+2x)^4(3x^2+2)^2+6x(x^3+2x)^5)

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(d^2)/(dx^2)((x^3+2x)^6)

\frac{d ^{2}}{d x ^{2}} ((x^{3} + 2 x)^{6})

6 (5 (x^{3} + 2 x)^{4} (3 x^{2} + 2)^{2} + 6 x (x^{3} + 2 x)^{5})

Solution steps

\frac{d ^{2}}{d x ^{2}} ((x^{3} + 2 x)^{6})

\frac{d}{d x} ((x^{3} + 2 x)^{6}) = 6 (x^{3} + 2 x)^{5} (3 x^{2} + 2)

= \frac{d}{d x} (6 (x^{3} + 2 x)^{5} (3 x^{2} + 2))

\frac{d}{d x} (6 (x^{3} + 2 x)^{5} (3 x^{2} + 2)) = 6 (5 (x^{3} + 2 x)^{4} (3 x^{2} + 2)^{2} + 6 x (x^{3} + 2 x)^{5})

= 6 (5 (x^{3} + 2 x)^{4} (3 x^{2} + 2)^{2} + 6 x (x^{3} + 2 x)^{5})

n = 0 \sum \infty (\frac{x}{n !})^{n}

y = (x + 4)^{5} (x + 1)^{2}

\int \frac{3 x ^{2} - 2}{( x + 2 ) ^{3}} d x

\int_{1}^{x} f (t) d t

x y (d x - d y) = x^{2} d y + y^{2} d x

What is (d^2)/(dx^2)((x^3+2x)^6) ?
The answer to (d^2)/(dx^2)((x^3+2x)^6) is 6(5(x^3+2x)^4(3x^2+2)^2+6x(x^3+2x)^5)