What is the derivative of (1+2x^2) ?

The derivative of (1+2x^2) is 4(1+2x)

What is the first derivative of (1+2x^2) ?

The first derivative of (1+2x^2) is 4(1+2x)

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\frac{d}{d x} ((1 + 2 x)^{2})

4 (1 + 2 x)

Solution steps

\frac{d}{d x} ((1 + 2 x)^{2})

Apply the chain rule:

2 (1 + 2 x) \frac{d}{d x} (1 + 2 x)

= 2 (1 + 2 x) \frac{d}{d x} (1 + 2 x)

\frac{d}{d x} (1 + 2 x) = 2

= 2 (1 + 2 x) \cdot 2

Simplify

= 4 (1 + 2 x)

\frac{1}{x ^{2}}

\int \frac{x + 1}{x ^{2} + 1} d x

f (x) = \frac{5}{2 5 x + 6}, at x = 2

\int \frac{11 x ^{2}}{( 36 + x ^{2} ) ^{2}} d x

\frac{20}{s ^{2} + 6 s + 144}

What is the derivative of (1+2x^2) ?
The derivative of (1+2x^2) is 4(1+2x)
What is the first derivative of (1+2x^2) ?
The first derivative of (1+2x^2) is 4(1+2x)