What is the integral of (x+1)/(sqrt(x^2+1)) ?

The integral of (x+1)/(sqrt(x^2+1)) is sqrt(x^2+1)+ln|sqrt(x^2+1)+x|+C

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integral of (x+1)/(sqrt(x^2+1))

\int \frac{x + 1}{x ^{2} + 1} d x

x^{2} + 1 + ln x^{2} + 1 + x + C

Solution steps

\int \frac{x + 1}{x ^{2} + 1} d x

Expand

\frac{x + 1}{x ^{2} + 1} : \frac{x}{x ^{2} + 1} + \frac{1}{x ^{2} + 1}

= \int \frac{x}{x ^{2} + 1} + \frac{1}{x ^{2} + 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ^{2} + 1} d x + \int \frac{1}{x ^{2} + 1} d x

\int \frac{x}{x ^{2} + 1} d x = x^{2} + 1

\int \frac{1}{x ^{2} + 1} d x = ln x^{2} + 1 + x

= x^{2} + 1 + ln x^{2} + 1 + x

Add a constant to the solution

= x^{2} + 1 + ln x^{2} + 1 + x + C

f (x) = \frac{5}{2 5 x + 6}, at x = 2

\int \frac{11 x ^{2}}{( 36 + x ^{2} ) ^{2}} d x

\frac{20}{s ^{2} + 6 s + 144}

\int x^{4} - 2 x d x

f (x) = (2^{x})^{8}

What is the integral of (x+1)/(sqrt(x^2+1)) ?
The integral of (x+1)/(sqrt(x^2+1)) is sqrt(x^2+1)+ln|sqrt(x^2+1)+x|+C