What is the derivative of f(x)=(2^x)^8 ?

The derivative of f(x)=(2^x)^8 is ln(2)*2^{8x+3}

What is the first derivative of f(x)=(2^x)^8 ?

The first derivative of f(x)=(2^x)^8 is ln(2)*2^{8x+3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = (2^{x})^{8}

ln (2) \cdot 2^{8 x + 3}

Solution steps

\frac{d}{d x} ((2^{x})^{8})

Simplify

(2^{x})^{8} : 25 6^{x}

= \frac{d}{d x} (25 6^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 25 6^{x} ln (256)

Simplify

25 6^{x} ln (256) : ln (2) \cdot 2^{8 x + 3}

= ln (2) \cdot 2^{8 x + 3}

x \to 0 - lim (\frac{1}{∣ x ∣})

\int z e^{z} d z

\frac{1}{( s - 1 ) ^{4}}

y = 10 + cot^{2} (x)

\frac{\partial}{\partial x} (arctan (x - y))

What is the derivative of f(x)=(2^x)^8 ?
The derivative of f(x)=(2^x)^8 is ln(2)*2^{8x+3}
What is the first derivative of f(x)=(2^x)^8 ?
The first derivative of f(x)=(2^x)^8 is ln(2)*2^{8x+3}