What is the derivative of y=sqrt(10+cot^2(x)) ?

The derivative of y=sqrt(10+cot^2(x)) is -(csc^2(x)cot(x))/(sqrt(10+cot^2(x)))

What is the first derivative of y=sqrt(10+cot^2(x)) ?

The first derivative of y=sqrt(10+cot^2(x)) is -(csc^2(x)cot(x))/(sqrt(10+cot^2(x)))

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derivative of

y = 10 + cot^{2} (x)

- \frac{csc ^{2} ( x ) cot ( x )}{10 + cot ^{2} ( x )}

Solution steps

\frac{d}{d x} (10 + cot^{2} (x))

Apply the chain rule:

\frac{1}{2 10 + cot ^{2} ( x )} \frac{d}{d x} (10 + cot^{2} (x))

= \frac{1}{2 10 + cot ^{2} ( x )} \frac{d}{d x} (10 + cot^{2} (x))

\frac{d}{d x} (10 + cot^{2} (x)) = - 2 csc^{2} (x) cot (x)

= \frac{1}{2 10 + cot ^{2} ( x )} (- 2 csc^{2} (x) cot (x))

Simplify

\frac{1}{2 10 + cot ^{2} ( x )} (- 2 csc^{2} (x) cot (x)) : - \frac{csc ^{2} ( x ) cot ( x )}{10 + cot ^{2} ( x )}

= - \frac{csc ^{2} ( x ) cot ( x )}{10 + cot ^{2} ( x )}

\frac{\partial}{\partial x} (arctan (x - y))

\frac{d}{d x} (\frac{8 e ^{x}}{2 e ^{x} + 1})

\int_{0}^{\frac{1}{2}} 1 - x^{2} d x

\int (1 - t) cos (t^{2} - 2 t) d t

\frac{d}{d x} (cos (x π))

What is the derivative of y=sqrt(10+cot^2(x)) ?
The derivative of y=sqrt(10+cot^2(x)) is -(csc^2(x)cot(x))/(sqrt(10+cot^2(x)))
What is the first derivative of y=sqrt(10+cot^2(x)) ?
The first derivative of y=sqrt(10+cot^2(x)) is -(csc^2(x)cot(x))/(sqrt(10+cot^2(x)))