What is (\partial}{\partial x}(\frac{arctan(*y^2))/x) ?

The answer to (\partial}{\partial x}(\frac{arctan(*y^2))/x) is -(arctan(y^2))/(x^2)

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(\partial}{\partial x}(\frac{arctan(*y^2))/x)

\frac{\partial}{\partial x} (\frac{arctan ( \cdot y ^{2} )}{x})

- \frac{arctan ( y ^{2} )}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{arctan ( y ^{2} )}{x})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= arctan (y^{2}) \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= arctan (y^{2}) \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= arctan (y^{2}) (- 1 \cdot x^{- 1 - 1})

Simplify

arctan (y^{2}) (- 1 \cdot x^{- 1 - 1}) : - \frac{arctan ( y ^{2} )}{x ^{2}}

= - \frac{arctan ( y ^{2} )}{x ^{2}}

\frac{d y}{d t} + e^{t} y = - e^{t}

2 y^{^{''}} + 3 y^{^{'}} + 9 y = 0

\frac{( x ^{4} - 5 x ^{3} + x )}{x ^{2}}

f (x) = (3 x^{2} - 2 x - 1)^{\frac{3}{2}}

\int \frac{38}{38 + e ^{x}} d x

What is (\partial}{\partial x}(\frac{arctan(*y^2))/x) ?
The answer to (\partial}{\partial x}(\frac{arctan(*y^2))/x) is -(arctan(y^2))/(x^2)