What is the solution for xy^'=2x^2y+3x^3e^{x^2},y(0)=5 ?

The solution for xy^'=2x^2y+3x^3e^{x^2},y(0)=5 is y=e^{x^2}x^3+5e^{x^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

xy^'=2x^2y+3x^3e^{x^2},y(0)=5

x y^{^{'}} = 2 x^{2} y + 3 x^{3} e^{x^{2}}, y (0) = 5

y = e^{x^{2}} x^{3} + 5 e^{x^{2}}

Solution steps

x y^{'} (x) = 2 x^{2} y + 3 x^{3} e^{x^{2}}

Solve linear ODE:

y = e^{x^{2}} x^{3} + 5 e^{x^{2}}

y = e^{x^{2}} x^{3} + 5 e^{x^{2}}

- x + 2, x^{2} - 1, [0, 1]

t sin (3 t)

\frac{\partial}{\partial x} (x^{2} + y^{2} - 25)

\frac{d}{d x} (2 x y + z^{2})

(x y) d x + x d y = 0

What is the solution for xy^'=2x^2y+3x^3e^{x^2},y(0)=5 ?
The solution for xy^'=2x^2y+3x^3e^{x^2},y(0)=5 is y=e^{x^2}x^3+5e^{x^2}