What is the d/(d{x)}(2{x}{y}+{z}^2) ?

The d/(d{x)}(2{x}{y}+{z}^2) is 2{y}

What is the first d/(d{x)}(2{x}{y}+{z}^2) ?

The first d/(d{x)}(2{x}{y}+{z}^2) is 2{y}

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\frac{d}{d x} (2 x y + z^{2})

2 y

Solution steps

\frac{d}{d x} (2 x y + z^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x y) + \frac{d}{d x} (z^{2})

\frac{d}{d x} (2 x y) = 2 y

\frac{d}{d x} (z^{2}) = 0

= 2 y + 0

Simplify

= 2 y

(x y) d x + x d y = 0

\int 5 x e^{3 x} d x

x \to 2 + lim (0)

\int - 10 t d t

f (x) = 5 x^{3} - 5 x, (1, 0)

What is the d/(d{x)}(2{x}{y}+{z}^2) ?
The d/(d{x)}(2{x}{y}+{z}^2) is 2{y}
What is the first d/(d{x)}(2{x}{y}+{z}^2) ?
The first d/(d{x)}(2{x}{y}+{z}^2) is 2{y}