What is the tangent of f(x)=5x^3-5x,(1,0) ?

The tangent of f(x)=5x^3-5x,(1,0) is y=10x-10

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tangent of f(x)=5x^3-5x,(1,0)

tangent of

f (x) = 5 x^{3} - 5 x, (1, 0)

y = 10 x - 10

Solution steps

Find the slope of

f (x) = 5 x^{3} - 5 x : \frac{df ( x )}{d x} = 15 x^{2} - 5

Compute the slope of

f (x) = 5 x^{3} - 5 x

(1, 0) : m = 10

Find the line with slope m=

10

and passing through

(1, 0) : y = 10 x - 10

y = 10 x - 10

4 y^{^{''}} - y - 1 = 0

y^{^{'}} = x + y, y (0) = 4

\frac{d}{d x} (ln (cos (\frac{x - 1}{x})))

x \to 0 lim (x^{5} \cdot cos (\frac{1}{x}))

\int (\frac{1}{x ^{5}}) d x

What is the tangent of f(x)=5x^3-5x,(1,0) ?
The tangent of f(x)=5x^3-5x,(1,0) is y=10x-10