What is the derivative of x^3+3x+2 ?

The derivative of x^3+3x+2 is 3x^2+3

What is the first derivative of x^3+3x+2 ?

The first derivative of x^3+3x+2 is 3x^2+3

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\frac{d}{d x} (x^{3} + 3 x + 2)

3 x^{2} + 3

Solution steps

\frac{d}{d x} (x^{3} + 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 3 x^{2} + 3 + 0

Simplify

= 3 x^{2} + 3

\int \frac{x}{3 x ^{2} + 2} d x

6 e^{6 e^{x} + x}

(x^{3} + 7) e^{x}

f (x) = - 1 x^{- \frac{3}{5}}

\frac{d}{d x} (cos (\frac{x}{y}))

What is the derivative of x^3+3x+2 ?
The derivative of x^3+3x+2 is 3x^2+3
What is the first derivative of x^3+3x+2 ?
The first derivative of x^3+3x+2 is 3x^2+3