What is the tangent of f(x)=sqrt(3x+4),(7,5) ?

The tangent of f(x)=sqrt(3x+4),(7,5) is y= 3/10 x+29/10

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tangent of f(x)=sqrt(3x+4),(7,5)

tangent of

f (x) = 3 x + 4, (7, 5)

y = \frac{3}{10} x + \frac{29}{10}

Solution steps

Find the slope of

f (x) = 3 x + 4 : \frac{df ( x )}{d x} = \frac{3}{2 3 x + 4}

Compute the slope of

f (x) = 3 x + 4

(7, 5) : m = \frac{3}{10}

Find the line with slope m=

\frac{3}{10}

and passing through

(7, 5) : y = \frac{3}{10} x + \frac{29}{10}

y = \frac{3}{10} x + \frac{29}{10}

\frac{\partial}{\partial x} (0.1 \cdot y^{2} + 0.05 \cdot x \cdot y)

\int (sec (x)) d x

\frac{d}{d x} (arcsin (6 x))

\frac{d}{d x} (3 arcsinh (tan (x)))

cos (- 5 x)

What is the tangent of f(x)=sqrt(3x+4),(7,5) ?
The tangent of f(x)=sqrt(3x+4),(7,5) is y= 3/10 x+29/10