What is the solution for ydy=-xdx ?

The solution for ydy=-xdx is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}

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ydy=-xdx

y d y = - x d x

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

Solution steps

y d y = - x d x

Solve separable ODE:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

\frac{\partial}{\partial x} (x^{2} - 0.1 \cdot cos (6 \cdot x))

\frac{d y}{d x} = 3 + e^{- 3 x + y + 4}

\int (x^{2} + 1) x - 2 d x

\int_{0}^{1} \frac{1}{t ^{2} + 1} d t

\frac{2 x + 2 y - 3}{- x - y - 1} = \frac{d y}{d x}

What is the solution for ydy=-xdx ?
The solution for ydy=-xdx is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}