What is the integral of xe^{x-1} ?

The integral of xe^{x-1} is e^{x-1}x-e^{x-1}+C

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integral of xe^{x-1}

\int x e^{x - 1} d x

e^{x - 1} x - e^{x - 1} + C

Solution steps

\int x e^{x - 1} d x

Apply Integration By Parts

: e^{x - 1} x - \int e^{x - 1} d x

= e^{x - 1} x - \int e^{x - 1} d x

\int e^{x - 1} d x = e^{x - 1}

= e^{x - 1} x - e^{x - 1}

Add a constant to the solution

= e^{x - 1} x - e^{x - 1} + C

\frac{\partial}{\partial x} (y \cdot x)

x \to 6 lim (2 x + 3 x)

x \frac{d y}{d x} + y = 2 x + 1

tan^{2} (9 x)

f (x) = (x^{2} - 3 x) (5 x^{3} + 6)

What is the integral of xe^{x-1} ?
The integral of xe^{x-1} is e^{x-1}x-e^{x-1}+C