What is the derivative of tan^2(9x) ?

The derivative of tan^2(9x) is 18sec^2(9x)tan(9x)

What is the first derivative of tan^2(9x) ?

The first derivative of tan^2(9x) is 18sec^2(9x)tan(9x)

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derivative of

tan^{2} (9 x)

18 sec^{2} (9 x) tan (9 x)

Solution steps

\frac{d}{d x} (tan^{2} (9 x))

Apply the chain rule:

2 tan (9 x) \frac{d}{d x} (tan (9 x))

= 2 tan (9 x) \frac{d}{d x} (tan (9 x))

\frac{d}{d x} (tan (9 x)) = sec^{2} (9 x) \cdot 9

= 2 tan (9 x) sec^{2} (9 x) \cdot 9

Simplify

= 18 sec^{2} (9 x) tan (9 x)

f (x) = (x^{2} - 3 x) (5 x^{3} + 6)

y^{^{'}} = e^{2 x} + y - 1

x \to 4 lim (x^{2} - 9)

2 x^{^{''}} + 6 x^{^{'}} + 9 x = 0

(2 x y + x) d x + (x^{2} + y) d y = 0

What is the derivative of tan^2(9x) ?
The derivative of tan^2(9x) is 18sec^2(9x)tan(9x)
What is the first derivative of tan^2(9x) ?
The first derivative of tan^2(9x) is 18sec^2(9x)tan(9x)