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Popular >

y^'=e^{2x}+y-1

Solution

y^{^{'}} = e^{2 x} + y - 1

Solution

y = 2 e^{x} cosh (x) + c_{1} e^{x}

Solution steps

y^{'} (x) = e^{2 x} + y - 1

Solve linear ODE:

y = 2 e^{x} cosh (x) + c_{1} e^{x}

y = 2 e^{x} cosh (x) + c_{1} e^{x}

Popular Examples

limit as x approaches 4 of sqrt(x^2-9)

x \to 4 lim (x^{2} - 9)

2x^{''}+6x^'+9x=0

2 x^{^{''}} + 6 x^{^{'}} + 9 x = 0

(2xy+x)dx+(x^2+y)dy=0

(2 x y + x) d x + (x^{2} + y) d y = 0

integral of 9.8x

\int 9.8 x d x

(\partial)/(\partial t)(0)

\frac{\partial}{\partial t} (0)

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{2x}+y-1 ?
The solution for y^'=e^{2x}+y-1 is y=2e^xcosh(x)+c_{1}e^x