What is the derivative of (7x-4/(-3x+3)) ?

The derivative of (7x-4/(-3x+3)) is 1/((x-1)^2)

What is the first derivative of (7x-4/(-3x+3)) ?

The first derivative of (7x-4/(-3x+3)) is 1/((x-1)^2)

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\frac{d}{d x} (\frac{7 x - 4}{- 3 x + 3})

\frac{1}{( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7 x - 4}{- 3 x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 7 x - 4 ) ( - 3 x + 3 ) - \frac{d}{d x} ( - 3 x + 3 ) ( 7 x - 4 )}{( - 3 x + 3 ) ^{2}}

\frac{d}{d x} (7 x - 4) = 7

\frac{d}{d x} (- 3 x + 3) = - 3

= \frac{7 ( - 3 x + 3 ) - ( - 3 ) ( 7 x - 4 )}{( - 3 x + 3 ) ^{2}}

Simplify

\frac{7 ( - 3 x + 3 ) - ( - 3 ) ( 7 x - 4 )}{( - 3 x + 3 ) ^{2}} : \frac{1}{( x - 1 ) ^{2}}

= \frac{1}{( x - 1 ) ^{2}}

- 6

x \to 5 lim (2 x - 5)

\frac{d y}{d t} = (1 + t) (1 + y)

t \to 1 + lim (\frac{∣ 1 - t ∣}{1 - t})

\frac{d}{d x} (e^{x^{2} - y^{2}})

What is the derivative of (7x-4/(-3x+3)) ?
The derivative of (7x-4/(-3x+3)) is 1/((x-1)^2)
What is the first derivative of (7x-4/(-3x+3)) ?
The first derivative of (7x-4/(-3x+3)) is 1/((x-1)^2)